2017 Spring Exam Question 4
From what I have got in question (d) and (e),
p(x) = x + 7/6x(x-1)
0 < ksi < 1
Error formula = (15/8 ksi(^-1/2))/(6) x(x-1)(x-1/4)
With the above information, I’ve concluded that we can’t find the bound in question (f) as ksi = 0 will lead to the bound being undefined. Can someone verify this is a valid conclusion and if not,please explain under what condition we won’t be able to find the upper bound. Thanks!